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in past exams the appropriate answer was "uncertain" i believe if it lies outside of the allowable increase/decrease, because you simply don't know
How do you determine whether you assign the last job to Machine 1 or Machine 2 in the Johnson's Rule ? Do you just assign it to the Machine that is faster (lower number of processing hours) ? Thanks !
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wrong course bro
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How did you adjust the size of the page? I'm trying to do one for another course and I can't make it the right size to print..
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How did you adjust the size of the page? I'm trying to do one for another course and I can't make it the right size to print..
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How did you adjust the size of the page? I'm trying to do one for another course and I can't make it the right size to print..
Can someone PLEASE upload a picture of the correct level plan? It's so easy but I keep making one mistake and it would help me a ton to just see the TABLE! Much much much appreciated!!! <3
there you go!
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For Open Question 3D, which formula do we use for this?
Can someone explain how to solve this one please?
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Get it but what does the number in the third column stand for?
These are the t-stats !
Why does the answer key contain two answers?
for the other values in the table it seems as the second value is just the first one rounded, but here this is not the case.
366/2*0,3=54,9 and 365,15/2*0,3=54,75
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how do you calculate MC question 10? thx
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thank you much!! and how do you calculate the utilities?
For the two products you add the intercept and the relevant coefficients: 1) 78.61 + 18.09 + 0 (this is de base variable) - 15.75 - 8.25 = 72.7 2) 78.61 + 0 + 0 + 0 + 0 Hope this helps :)
Where are the 14.73 coming from?
same question!
Answered above :)
Do you guys know how to find this?
Answered above :)
isn't objective function min(T- y1- y2-...-y7)
I don't think E+D or B + F are feasible crash combinations... so for the second round it would just be crash either A, G or B+C... right?
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Ah you’re semi right. So E and D work because there is at least one of the two on all three critical path options. For B and F you’re right because it only covers 2/3 paths.
the right answer is t crash A (week 1) and F+B (week2). first calculate the incremental cost for each activity which is the difference between the normal and the crashing cost. then you'll crash the activities with the overall cheapest incremental costs.
can someone explain how did we get 23 ?
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I didn't see correctly i thought it was the sign lower or equal 23 and not 523 ! My bad thank you
but they ask for the amount of "profit" it should decrease by, so 523*7500 = 3922500
Shouldn't the answer be D, due to the fact that you otherwise invest 75% of your money in Non-Buyers? At least that is what the Prof. said in the recap lecture.
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Well to me both answers make sense; for C) we have a bigger count and for D) we have a higher percentage of potential buyers but at the bottom of this document there is an answer sheet to the MC part and there it is said it's D) (which I guess is correct as all the other answers seem to be correct)
alright thanks, I guess I will write segment 4 when it comes in the exam
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It is Min. T for Q3 C
They claimed they want to make sure the house is finished as soon as possible and that they have a budget. Shouldn't be better to add the crashing cost (e.g 400C1 etc.) to the objective function too ? The cost should be minimized too as previously done in assignment 12
Victor, Well I don't think so since they are not trying to minimize cost. They do have a budget but it just means that the costs needs to be within that budget which we define in the contraints in question 3 D In assignment 12 the main focus is to crush activities within the set time period to avoid additional costs, meaning the main focus is on the costs. So I think the right answer is minimise (T)!
Shoudn't we multiply by the lead time as well ? so 1,64x20xSQR*2 ?
Yes, they made a mistake there The right answer is 46.67
isn't the answer to this E? I got utility of 78.61 for A and utility of 78.8 for E?
How do you calculate this?
You add the coefficients and the intercept. In this exercise the correct answer is e) and you can find that by doing the following: 78.61 + 17.86 + 0 - 15.75 - 1.92 = 78.8 Just in case you wonder where the 0 comes from this is our base level (so basically if the characteristic is not in the table it's coefficient is 0; 20cl is our base level so is 0) Hope this helps :)
How can you interpret this without knowing the dimensions?
You have to look at the word associations of all the extremes in the graph (the outliers). They will ask you for example what the main word would be for dimension 2 so you look at the outliers from dimension 2 and see which word association is reoccuring. Same for the other dimensions. Hope this helped you out a little
I think this is supposed to be n=3 Since you take the averages of the samples, making in theoretically 1 sample and 3 observations LCL = 0 * 1.72 = 0 UCL = 2.57 * 1.72 = 4.42
Yep I have the same
how did you get there, cause whenever I try, I end up with B-F-C-A-E-D
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thanks you! I see what I did wrong now. I did (due - SUM of lowest CR)/time
No problem!
why is it 703236 and not 673800 ? (673800 being the old profit)
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Basically they ask you which option would be better (0.5 more capacity, 4 more storage, or 500 more hours processing) To find out which is better you just need to multiply these numbers by their respective shadow price's: Capacity: 0.5*23,333.33 = 11,666.67 Storage: 4*3833.33 = 15,333.32 Processing: 500*0 = 0 We can see here that the storage option is the better one! Hope this helped :)
great, got it! thanks!
It doesn't state that you can't crash a week twice, so the optimal solution would be to crash E&F by two weeks
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No Because E is on only two of the three critical paths. This means that you still have to shorten the third one to crash all three paths by one week.
I crashed F and E for the first week then for the second I crashed E and C. So I have an idle time of 1 in one of the critical path. Can I do that ? Because the job will be finish in 19 weeks anyway
What does this mean? and how do we find it out?
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Thanks but why is it - y_7 at the end not y_6?
Mmmh I think it's a typo but I could be wrong
The normal costs are not per week but in general e.i. 3000, so multiplying the remaining weeks, after deducting the crashed weeks, with the 3000 and so on is wrong right?
Then would the correct answer be B >= Sum of all (b_i + c_i * y_i)
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For open question 4c: could the budget constraints simply be that for example: Xch=0 ; Xcr=0 ?
Hey! Is there anyone who can help me with Q13? How would you draw this graph?
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The timeline task was a lot clearer to me somehow :D Thanks for making the connection!
Just in case it's still a bit unclear; there's a similar exercise on the 2013 exam! Should sort you out :)
Can someone explain the budget constraint please?
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can someone explain q13
did you get an answer or know how to solve it? i am still struggling to get it
The closest you are to 0 the more similar it is. So, if you compare Heineken and Jupiler = 4 Heineken & Maes = 5 Heineken & Cristal =1 The most similar to Heineken is Cristal then Jupiler then Maes. I think that the distances will be in relation to these different numbers but I am not sure
Where is the 80 000 coming from?
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Basically the 118,000 is the maximum revenue you could get by knowing the demand (maximum demand for every alternative) and the 80,000 is the max profit you can make by choosing only 1 alternative. So if you know the demand you would make 38,000 more profit than if you did not. --> Which means you can pay up to 38,000 to know the future demand (if you payed 37,000 you'd still make 1000 of profit) Hope this helps! :)
Got it thanks!
I think you forgot to take into account that you need 20 units in ending inventory!! So it would be more expensive...
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oh sorry I have 97750 for a now actually...
can anyone explain how they accounted for the ending inventory? since they cannot be produced in the last month, for subcontracting capacity reasons.
should it not be like this????? you have to look at the difference! and I think the normal cost should be the cost per week, because otherwise you get negative values and then crashing would not make sense..
I don't think it is correct, why do you subtract crash cost from normal cost before calculating the amount of crashing weeks? and in the exam comments, the course coordinator mentioned that the normal cost is not in weeks but it is the entire cost. so the answer is 78500
yes thanks! i have it now! thankyou
I thought answer c was not right either because if you are with D, you would rather stay there because 0.5 > 0.3 (D -> E). Why is going from D to E still a valid option?
but when c is d why is then d not c if 0,5>0,3 and the moving average is bigger than the size of your socks?
You are talking about question 12 right? The answer is C because they say the customer is likely to go to brand D OR brand E. Doesn't matter what they choose, it just shows that they have the probability go to D OR E.
Can someone explain how to do this? I understand the examples in the book, but this one not....
Maximum cutoff value means the highest value in that category and lexicographic rule chooses the highest value in one aspect as well. For example when we are looking at Design. Cutoff value would be 9 as it is the highest number (conjunctive) and lexicographic would choose 9 as well as its the highest value in that category (design)
What is the correct answer? I don't really get the answers..
I think the answer is B. A. doesn't make sense because the brand switching matrix doesn't show probability of buying one brand alone C is incorrect because the probability is 0.5 D 0 percent doesn't mean they CANNOT buy it in the next COMING periods E They have the chance to buy it, Not that they will buy it
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Can someone explain why it is C) informative - entertainment ?
How can you determine the number of clusters just from looking at the agglomeration schedule? Why is it 4 clusters here? Thanks!
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what a legend :) second time you saved my ass, feeling much better about the upcoming resit already! thanks a lot!
No problem! Feels nice to help people when you can (and also allows me to check I'm ready for that killer resit)
How to solve these two tasks? Any ideas :)?